Question

A sample of iron absorbs 67.5 J of heat, upon which the temperature of the sample

increases from 21.5 °C to 28.5 °C. If the specific heat of iron is 0.450 J/g OC, what is
the mass (in grams) of the sample?

Answer 1

Step-by-step explanation:

Observe the units of all of the prameters to solve this problem

m * (28.5-21.5)C * .450 J/(gC) = 67.5 J

m * 7 * .450 = 67.5

m = 67.5/(7 * .450) = 21.4 grams