Question

You have a 0.0675 M solution of Ca(OH)2, what is the pOH of your solution?

pOH= _________(round to 3 sig figs)

This solution is _________(acidic/basic).

(30 points)

Answer 1

Calcium hydroxide (Ca(OH)2) is a strong base that dissociates completely in water to form calcium ions (Ca2+) and hydroxide ions (OH-).

The balanced chemical equation for the reaction of Ca(OH)2 in water is:

Ca(OH)2 → Ca2+ + 2 OH-

In this case, the initial concentration of Ca(OH)2 is 0.0675 M.

Since each mole of Ca(OH)2 produces two moles of OH-, the concentration of OH- in the solution can be calculated as follows:

[OH-] = 2 x 0.0675 M = 0.135 M

Now, we can use the following equation to find the pOH of the solution:

pOH = -log[OH-] = -log(0.135) = 0.869

Therefore, the pOH of the 0.0675 M Ca(OH)2 solution is 0.869.

To determine if the solution is acidic or basic, we can use the fact that pH + pOH = 14 for any aqueous solution at room temperature. In this case, the pH can be calculated as follows:

pH = 14 - pOH = 14 - 0.869 = 13.131

Since the pH is greater than 7, the solution is basic.