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What is an equation of the line that passes through the points (4, -2) and (- 1, 3)?

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To find the equation of the line that passes through the points (4, -2) and (-1, 3), we can use the point-slope form of a linear equation, which is:

y - y1 = m(x - x1)

where m is the slope of the line, and (x1, y1) is one of the given points.

First, we can find the slope of the line using the two points:

m = (y2 - y1) / (x2 - x1)

m = (3 - (-2)) / (-1 - 4)

m = 5 / (-5)

m = -1

Next, we can choose one of the points to plug into the point-slope form. Let's choose the point (4, -2):

y - (-2) = -1(x - 4)

Simplifying this equation, we get:

y + 2 = -x + 4

Subtracting 2 from both sides, we get:

y = -x + 2

Therefore, the equation of the line that passes through the points (4, -2) and (-1, 3) is y = -x + 2.

User Idan Wender
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