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Determine which acute angle has a cos of 8/17

Determine which acute angle has a cos of 8/17-example-1
User Nomi Ali
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1 Answer

5 votes

Answer:


\large\boxed{\tt \angle L}

Explanation:


\textsf{We are asked which angle has a Cosine of} \ \tt (8)/(17) .


\textsf{As you may have spotted, there's no 8 or 17 for any side of the triangle. This}


\textsf{identifies that we can reduce the fraction we will find out.}


\large\underline{\textsf{What is Cosine?}}


\textsf{Cosine is the \textsf{Trigonometric Ratio} between the Adjacent Side, and the Hypotenuse}


\textsf{of a triangle.}


\boxed{\begin{minipage}{15 em} \underline{\textsf{\large Cosine Trigonometric Formula;}} \\ \\ \textsf{ Cosine = {A}/{H} }\\ \\ \underline{\textsf{\large Where;}} \\ \textsf{A = The Adjacent SIde.} \\ \textsf{H = The Hypotenuse.} \end{minipage}}


\textsf{We should find the Cosine of every angle for this triangle.} \ \tt (\angle K, \ \angle L, \ \angle M)


\large\underline{\textsf{Finding the Cosine of} \ \tt \angle K;}


\textsf{Unfortunately, } \tt \angle K \ \textsf{is a right angle, hence it has 2 Adjacent Sides.}


\textsf{K doesn't have a Cosine, meaning it's incorrect.}


\large\underline{\textsf{Finding the Cosine of} \ \tt \angle M;}


\tt \angle M \ \textsf{is not a right angle, hence it will have an Adjacent Side and a Hypotenuse.}


\large\underline{\textsf{Review of what an Adjacent Angle is;}}


\textsf{The Adjacent side is not the Hypotenuse, but the side that the angle is formed by.}


\textsf{The Adjacent Side is the side that the angle is formed by.}


\textsf{The Adjacent Side of} \ \tt \angle M \ \textsf{is the side with the length of 30.}


\textsf{The Hypotenuse will always be the side with the largest length.}


\underline{\textsf{We should have;}}


\tt (30)/(34) \overset{Divide \ by \ 2/2}{\rightarrow} (15)/(17)


\textsf{The reduced fraction doesn't match with} \ \tt (8)/(17) .


\tt \angle M \ \textsf{is incorrect.}


\large\underline{\textsf{Finding the Cosine of} \ \tt \angle L;}


\tt \angle L \ \textsf{is not a right angle, hence it will have an Adjacent Side and a Hypotenuse.}


\textsf{The Adjacent Side of} \ \tt \angle L \ \textsf{is the side with the length of 16.}


\textsf{The Hypotenuse for} \ \tt \angle L \ \textsf{will be 34.}


\underline{\textsf{We should have;}}


\tt (16)/(34) \overset{Divide \ by \ 2/2}{\rightarrow} (8)/(17) \ \checkmark


\large\boxed{\tt \angle L \ \textsf{is correct.}}

User Anastasia Black
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