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Factorise (a-b+c)²-(b-c+a)²​

User Tdimmig
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Answer: (a-b+c)²-(b-c+a)²​

=((a-b+c)) - ((b-c+a)) ((a-b+c)) - ((b-c+a))

= (a-b+c-b+c-a) ( a-b+c+b-c+a)

= (-2b + 2c ) (2a)

= (2( -2b/2+2c/2)) (2a)

=(2(-b+c)) (2a)

=2(-b+c) (2a)

User Rz Mk
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