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Write a program that reads the content of a text file called text.txt. the program should create a dictionary in which the keys are individual words found in the file and the values are the amount of times the word appears in the file. For example, if the word 'the' appears in the file 128 times, the dictionary would contain an element with the key as 'the' and the value as 128. Write in Python

User Luis Lopez
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Answer:

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# Open the text file for reading

with open('text.txt', 'r') as file:

# Initialize an empty dictionary to store word counts

word_counts = {}

# Loop through each line in the file

for line in file:

# Split the line into individual words

words = line.split()

# Loop through each word in the line

for word in words:

# Remove any punctuation from the word

word = word.strip('.,;:?!')

# Convert the word to lowercase

word = word.lower()

# If the word is already in the dictionary, increment its count

if word in word_counts:

word_counts[word] += 1

# If the word is not yet in the dictionary, add it with a count of 1

else:

word_counts[word] = 1

# Print the resulting word count dictionary

print(word_counts)

Step-by-step explanation:

This code uses the open() function to open the "text.txt" file for reading, and then reads each line of the file using a for loop. Each line is split into individual words using the split() method, and then each word is cleaned up by removing any punctuation and converting it to lowercase. The code then adds each word to a dictionary and counts the number of occurrences of each word. Finally, the resulting dictionary of word counts is printed to the console.

User Pandurang Yachwad
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