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What is the resistance of a bulb when it draws 0.25A from a 24V battery source?

User Nserror
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1 Answer

3 votes

Solution:

We are given,

Curr ent (I) = 0.25 A

Voltage (V) = 25 V

According to Ohm's law.


\sf \: \: \: \: \: \: R = (V)/(I)

Substituting the values of V and I in above formula,


\sf R = (25)/(0.25) \\ \\ \sf R =100 Ω

Therefore, The resistance of the bulb will be 100Ω.

User Pau Trepat
by
8.2k points