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What is the rate of the growth of the equation below

254,000(1.125)^t

User Matheno
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1 Answer

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Answer: 12.5%

Step-by-step explanation:

Rewrite the 1.125 as 1+0.125

So we have the equation y = 254000(1+0.125)^t

Compare that to y = a(1+r)^t and you'll find that r = 0.125

In other words, solving 1+r = 1.125 leads to r = 0.125

That corresponds to a 12.5% growth rate. If r was negative, then you'd have exponential decay.

User Tarun Reddy
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