Question

Calculate the distance between the points Q=(-7,-5) and J= (1, 3) in the coordinate plane.

Round your answer to the nearest hundredth.
-10 -S -6
2
10-
2
6
on
10
Distance:

Answer 1

`~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Q(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-5})\qquad J(\stackrel{x_2}{1}~,~\stackrel{y_2}{3})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ QJ=√((~~1 - (-7)~~)^2 + (~~3 - (-5)~~)^2) \implies QJ=√((1 +7)^2 + (3 +5)^2) \\\\\\ QJ=√(( 8 )^2 + ( 8 )^2) \implies QJ=√( 64 + 64 ) \implies QJ=√( 128 )\implies QJ\approx 11.31`