Answer: 0.01143 m/s
Step-by-step explanation:
use conservation of momentum, since momentum is always conserved. assume left of = is initial, to the right if final
m1v1=m1v1 + m2v2
(40)(20)=(40)(5) + (350)(v2)
solve for v2 (denoting velocity of bear)
yes, the bear will be moving, at a speed of 0.011428571 (round how you like)