Question

A cylindrical pool has a diameter of 16 ft and a height of 4ft. the pool is filled 1/2 foot below the top. how much water does the pool contain, to the nearest gallon?

1 feet cubic= 7.48 gallons

Answer choices are:
-704
-804
-5264
-6016

Answer 1

Explanation:

In this problem, we have to use the formula in finding the volume of a cylinder

`V=\pi r^(2) h`

r is half of diameter
r= 16ft / 2 = 8ft

The height of the cylinder is 4ft. We have to know the height of the water to know the volume of the water.

h (water) = 4ft - 1/2ft = 3.5ft

`V=\pi (8)^(2) (3.5)`

`V = 703.72 ft^(3)`

`V = 703.72 ft^(3) * (7.48 gallons)/(1ft^(3) )`

`V = 5263.8 gallons`

`V = 5264 gallons`

The pool is filled with 5264 gallons of water.