Answer: option B is correct ,H2O has lowest bond angle of 104.5 degreewith hybridization of sp3,
Explanation: In H2O there are two bond pair and two lone pair on the central atom. The repulsion in a molecule follow the order lone pair-lone pair>lone pair-bond pair> bone pair-bone pair.
Due to the strong repulsion the presence of lone pair on central atom decreseas the bond angle in a molecule .
H2O ,CH4,NH4 has hybridization of sp3,
BF3 hybridization of sp2
bond angle of
CH4=109.5 degree
BF3=120 degree
NH4=109.5 degree
H2O =104.5 degree