To calculate the volume of 0.300M solution that contains 1.5g of the solute, we need to use the following formula:
moles of solute = mass of solute / molar mass of solute
moles of solute = (1.5g) / (1 x H + 1 x S + 3 x O) g/mol
moles of solute = (1.5g) / (1 + 32 + 3x16) g/mol
moles of solute = (1.5g) / 98 g/mol
moles of solute = 0.015306 moles
Now, we can use the following formula to calculate the volume of the solution:
moles of solute = molarity x volume (in liters)
0.015306 moles = 0.300 M x volume (in liters)
volume (in liters) = 0.015306 moles / 0.300 M
volume (in liters) = 0.05102 L
Finally, we can convert the volume from liters to milliliters (mL):
volume (in mL) = 0.05102 L x 1000 mL/L
volume (in mL) = 51.02 mL
Therefore, 51.02 mL of 0.300M solution would contain 1.5g of solute.