Answer:
The given expression is:
p^2 + 4q^2 + 9 + 36 + pq + 3 + 4q + 6p
Rearranging the terms, we get:
p^2 + 6p + 4q^2 + pq + 4q + 48
Now, we can group the first three terms and the last three terms together as follows:
(p^2 + 6p + 9) + (4q^2 + pq + 4q + 39)
The first group can be factorized as a perfect square trinomial:
(p + 3)^2
The second group can be factorized by grouping the first two terms and the last two terms:
(pq + 4q) + (4q^2 + 39)
We can factor out q from the first two terms, and 4 from the last two terms:
q(p + 4) + 4( q^2 + 9)
Now, we can factor the second group as a sum of squares:
q(p + 4) + 4(q + 3)(q - 3)
Therefore, the fully factorized form of the expression is:
(p + 3)^2 + q(p + 4) + 4(q + 3)(q - 3) + 48
Note that this expression cannot be simplified further.