Let's assume that Mr. Paquette has x pencils.
From the problem, we know that for each pencil he has, he also has 3 pens. So the total number of pens he has is 3 times the number of pencils:
Number of pencils = x
Number of pens = 3x
The total number of pencils and pens combined is given as 8, so we can write:
x + 3x = 8
Simplifying, we get:
4x = 8
x = 2
Therefore, Mr. Paquette has 2 pencils and 3x2=6 pens.