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A'(B+C') do minterm maxterm

User Mrzo
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Assuming that A', B, and C' are Boolean variables, the expression A'(B+C') can be simplified using Boolean algebra rules:


\rm A'(B+C') = A'B + A'C'

This expression is in the form of the sum of two products (or minterms), where the first minterm is A'B and the second minterm is A'C'.

To convert this expression to a maxterm, we can use De Morgan's theorem, which states that the complement of a product is equal to the sum of the complements of its terms. Therefore:


\rm \: A'(B+C') = A'B + A'C'


\rm \: = (A'+B') + (A'+C')

This expression is in the form of the sum of two sums (or maxterms), where the first maxterm is (A'+B') and the second maxterm is (A'+C').

User Rthbound
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