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Find the 9th term of the geometric sequence whose common ration is 2/3 and whose first term is 6.

User Kahiem
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Answer:

To find the 9th term of a geometric sequence, we can use the formula:

an = a1 * r^(n-1)

where:

an = the nth term of the sequence

a1 = the first term of the sequence

r = the common ratio of the sequence

n = the term number we want to find

In this case, we are given that the common ratio is 2/3, the first term is 6, and we want to find the 9th term. So we can plug in those values and get:

a9 = 6 * (2/3)^(9-1)

Simplifying the exponent, we get:

a9 = 6 * (2/3)^8

Using a calculator, we can evaluate the exponent:

a9 = 6 * 0.015625

Multiplying, we get:

a9 = 0.09375

Therefore, the 9th term of the geometric sequence is 0.09375.

Explanation:

here's a step-by-step explanation:

We are given the first term of the geometric sequence, a1 = 6, and the common ratio, r = 2/3. We need to find the 9th term, which we can do using the formula:

an = a1 * r^(n-1)

where n is the term number we want to find.

Step 1: Substitute the given values into the formula

a9 = 6 * (2/3)^(9-1)

Step 2: Simplify the exponent

a9 = 6 * (2/3)^8

The exponent 9-1 simplifies to 8.

Step 3: Evaluate the exponent

a9 = 6 * 0.015625

We can use a calculator to evaluate (2/3)^8, which is 0.015625.

Step 4: Multiply to find the 9th term

a9 = 0.09375

Multiplying 6 by 0.015625 gives us the 9th term of the geometric sequence, which is 0.09375.

Therefore, the 9th term of the geometric sequence whose common ratio is 2/3 and whose first term is 6 is 0.09375.

User Mario Camilleri
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