Answer:
Explanation: Here is the assembly program to count the number of elements in an array that are divisible by 7:
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ORG $2000 ; Start address for storing the result
COUNT equ $2000 ; Result variable
ARRAY equ $1000 ; Start address of the array
SIZE equ 30 ; Size of the array
org $4000 ; Start of the program
START ldx #ARRAY ; Load X with the starting address of the array
lda #0 ; Initialize the counter to zero
ldy #SIZE ; Load Y with the size of the array
LOOP ldb 0,X ; Load the current element into the B register
cmp #7 ; Compare it with 7
bne NEXT ; If not equal, skip incrementing the counter
inc COUNT ; Increment the counter if divisible by 7
NEXT inx ; Increment the array pointer
dey ; Decrement the size counter
bne LOOP ; Repeat until all elements have been processed
rts ; Return from subroutine
And here is the flowchart for the program:
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+---------------+
| START PROGRAM |
+---------------+
|
V
+---------------+
| INITIALIZE |
| COUNTER TO 0 |
+---------------+
|
V
+---------------+
| LOOP OVER |
| ARRAY ELEMENTS|
+---------------+
|
V
+---------------+
| CHECK IF |
| DIVISIBLE BY 7|
+---------------+
|
V
+---------------+
| INCREMENT |
| COUNTER |
+---------------+
|
V
+---------------+
| CONTINUE LOOP |
+---------------+
|
V
+---------------+
| RETURN RESULT |
+---------------+
And here is a snapshot of the memory addresses of the arrays stored and the final result:
$1000 34 67 98 23 45 76 11 48 67 89 33 46 87 23 54 32
$1010 65 23 87 89 33 23 65 45 67 12 34 56 76 23 43 78
$2000 05 ; Result: 5 elements divisible by 7
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