Answer:
PE = 1/2 K x^2 potential energy
when x = A
PEt = 1/2 k A^2 total potential energy
If x = A / 2
PE 1/2= 1/2 k A^2 / 4
PE1/2 / PEt = 1/4
Thus the PE at 1/2 the displacement is 1/4 the total
Since PE + KE = constant
3/4 the mass's energy will be KE at 1/2 the amplitude