Answer:
(I) - B
(II) - C
(III) - C
(IV) - D
Step-by-step explanation:
(I) both of carboxylic acids (B) and alcohols (E) are miscible in H2O, but carboxylic acids increase the acidity of water/solution
(II) Saturated hydrocarbons are from alkane hydrocarbons and they don't have pi bonds, only sigma bonds, and (C) is an alkane (Propane).
(III) Alkanes (C) are unreactive because of sigma bonds which are strong bonds that needs high energy to break
(IV) any unsaturated hydrocarbon (having pi bonds or double bonds, "==" in Lewis Structure) decolourizes Br2 since Br atoms react with the unsaturated hydrocarbon, producing bromo-alkane, for instance, 1-propene (D) + Br2 ---> 1-bromo propane