Question

The football booster club raised $750 to take a group of students to a football game. The booster club will pay for the bus to transport the students to the game, the admission tickets to the game, and a meal at the concession stand for each student. The bus to transport the students to the game costs $200. Each admission ticket to the game costs $6.50.If the booster club pays for a medium sandwich, drink, and popcorn for each student, how many more students can go to the game than if the booster club pays for a large sandwich, drink, and popcorn for each student?

Answer 1

Let's first find the total cost of transportation and admission tickets:

$200 (transportation) + $6.50 (admission ticket) x n (number of students) = $750

$6.50n = $550

n = 84.62

So, the maximum number of students that can go to the game is 84.62. However, we cannot have a fractional number of students, so we can round down to 84 students.

Now, let's find the cost of the meal for each student:

$2.50 (medium sandwich) + $2.00 (drink) + $1.50 (popcorn) = $6.00

If the booster club pays for a large sandwich, drink, and popcorn for each student, the cost will be:

$3.00 (large sandwich) + $2.50 (drink) + $2.00 (popcorn) = $7.50

The difference in cost between the two options is $1.50 per student.

To find how many more students can go to the game with the cheaper meal option, we can divide the total amount of money available ($750) by the difference in cost per student ($1.50):

$750 ÷ $1.50 = 500

So, with the cheaper meal option, the booster club can take 500/6 students = 83 students.

Therefore, the booster club can take 1 more student to the game if they pay for a medium sandwich, drink, and popcorn for each student.