Question

pls help!!! right answer only!! Find the equation of a line perpendicular to y= −3x − 10 that passes through the point (9,−2).

Answer 1

y =
`(1)/(3)` x - 5

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x - 10 ← is in slope- intercept form

with slope m = - 3

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-3)` =
`(1)/(3)` , then

y =
`(1)/(3)` x + c ← is the partial equation

to find c substitute (9, - 2 ) into the partial equation

- 2 =
`(1)/(3)` (9) + c = 3 + c ( subtract 3 from both sides )

- 5 = c

y =
`(1)/(3)` x - 5 ← equation of perpendicular line