Final answer:
The mass of the oxygen used during the reaction is 1.48 grams, calculated by subtracting the mass of iron from the mass of the iron oxide.
Step-by-step explanation:
The mass of the oxygen used during the reaction can be calculated by the difference in mass between the iron and iron oxide. Given iron (Fe) has a mass of 19.43 grams and the resulting iron oxide (Fe2O3) has a mass of 20.91 grams, the mass of the oxygen (O2) used can be determined by subtracting the mass of the iron from the mass of the iron oxide.
The calculation is as follows:
- Mass of iron oxide (Fe2O3) = 20.91 g
- Mass of iron (Fe) = 19.43 g
- Mass of oxygen (O2) = Mass of iron oxide - Mass of iron
- Mass of oxygen (O2) = 20.91 g - 19.43 g
- Mass of oxygen (O2) = 1.48 g
Therefore, 1.48 grams of oxygen were used in the reaction to form iron oxide from iron.