Y = 6/5x + 31/5 is the line's equation.
A line intersect in geometry is the intersection of two or more lines.
The point of intersection is the sole point that two lines have in common when they intersect.
The system of equations that the two lines form has its solution at this point of intersection.
The point-slope version of the equation of a line, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line, must be used to obtain distinct y-intercepts using the supplied slopes.
We can solve for y and set x = 0 to discover the y-intercept.
Let's select point (2, 3) on the line with slope 1/5. Using the form of point-slope, we obtain:
y - 3 = 1/5(x - 2)
y - 3 = 1/5x - 2/5
y is equal to 1/5x plus 13/5.
Y = 13/5 is the y-intercept when x = 0. Y = 1/5x + 13/5 is the line's equation.
Let's select the line's point (4, 2) for slope 3/5. Using the form of point-slope, we obtain:
y - 2 = 3/5(x - 4)
y - 2 = 3/5x - 12/5
y = 3/5x + 8/5
The y-intercept, y = 8/5, is obtained by setting x = 0. Thus, y = 3/5x + 8/5 is the line's equation.
Let's select the line's point (-1, 5) for slope 6/5. Using the form of point-slope, we obtain:
y - 5 = 6/5 (x + 1)
y - 5 = 6/5x + 6/5
y = 31/5 + 6/5x