Explanation:
A. To find the equation of a line parallel to line f (y = 2) and passing through point P(-2, -1), we need to understand that parallel lines have the same slope. Since line f is a horizontal line with a slope of 0, the line we are looking for will also have a slope of 0. The equation for a horizontal line with the same y-intercept as point P is simply y = -1.
B. To find the equation of a line parallel to line g (y = 2x - 1) and passing through point P(-2, -1), we need to consider that parallel lines have the same slope. The slope of line g is 2. Using the point-slope form (y - y1 = m(x - x1)), where m is the slope and (x1, y1) is the given point P(-2, -1):
y - (-1) = 2(x - (-2))
y + 1 = 2(x + 2)
Now, we can convert this to slope-intercept form (y = mx + b):
y = 2x + 4 - 1
y = 2x + 3
C. To find the equation of a line perpendicular to line f (y = 2) and passing through point Q(3, -2), we need to know that perpendicular lines have slopes that are negative reciprocals of each other. Since line f is a horizontal line with a slope of 0, the line perpendicular to it will be a vertical line. The equation for a vertical line passing through point Q with the same x-coordinate is simply x = 3.
D. To find the equation of a line perpendicular to line g (y = 2x - 1) and passing through point Q(3, -2), we need to find the negative reciprocal of the slope of line g. The slope of line g is 2, so the negative reciprocal is -1/2. Using the point-slope form (y - y1 = m(x - x1)), where m is the new slope and (x1, y1) is the given point Q(3, -2):y - (-2) = -1/2(x - 3)
y + 2 = -1/2(x - 3)
Now, we can convert this to slope-intercept form (y = mx + b):
y = -1/2x + 3/2 - 2
y = -1/2x - 1/2