Answer:
Therefore, the pressure of the gas at 273 K is approximately 0.312 atm.
Step-by-step explanation:
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
(P1 × V1) / T1 = (P2 × V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
We are given the initial pressure P1 = 0.370 atm and the initial temperature T1 = 50.0°C = 323 K. We want to find the final pressure P2 at a temperature of T2 = 273 K.
We can rearrange the formula above to solve for P2:
P2 = (P1 × V1 × T2) / (V2 × T1)
Since the volume of the gas is not changing, we can simplify this to:
P2 = (P1 × T2) / T1
Substituting the given values, we get:
P2 = (0.370 atm × 273 K) / 323 K
Simplifying, we get:
P2 ≈ 0.312 atm