Question

If k is a constant, what is the value of k so that the polynomial k²x³ - 8kx + 16 is divisible by x - 1?

(3) 8
(4) 16
(1) 2
(2) 4

Answer 1

Step-by-step explanation:

k²x³ - 8kx + 16=0;

since, k²x³ - 8kx + 16 is divisible by x - 1 then,

k²-8K+16=0;

k²-4K-4K+16=0;

k(k-4)-4(k-4)=0;

(k-4)(k-4)=0;

k=4