Answer: 200m in 5seconds.
Explanation: To find the distance traveled by the cyclist in 5 seconds, we need to use the equation for distance traveled with uniform acceleration:
d = d0 + v0t + 1/2a*t^2
where d is the distance traveled, d0 is the initial displacement (in this case, 0 since the cyclist starts from rest), v0 is the initial velocity (also 0 in this case), t is the time elapsed, and a is the acceleration.
We are given that the cyclist moves 8m in 4 seconds, so we can plug these values into the equation:
8m = 0 + 04s + 1/2a*4s^2
8m = 1/2a16s^2
a = 8m / (1/2 * 16s^2)
a = 16m/s^2
Now that we have the acceleration, we can use the equation to find the distance traveled in 5 seconds:
d = 0 + 05s + 1/216m/s^2*5s^2
d = 1/216m/s^225s^2
d = 200m
Therefore, the cyclist will move a distance of 200m in 5 seconds.