Answer:
(2) x = √34
(3) x = 2√5
Explanation:
You want the values of x in two different isosceles triangle figures.
(2)
We presume the triangle is isosceles, so the Pythagorean theorem tells us ...
3² + 5² = x²
x = √34 . . . . . . simplify, take the square root
(3)
The Pythagorean theorem tells us ...
(x/2)² +2² = 3²
x²/4 = 9 -4 . . . . . . subtract 2², expand the square involving x
x² = 4·5 . . . . . . multiply by 4
x = 2√5 . . . . take the square root