Answer:
(d³)⁵ (d³)⁰ = d^(3*5) * d^0 = d^15 * 1 = d^15
(2xy)³x² = (2^3 * x^3 * y^3) * x^2 = 8x^5y^3
(3b⁻²)²(a²b⁴)³ = (9b⁻⁴) * (a²b⁴)³ = 9a²b⁴*⁴ = 9a²bⁱ⁶
Explanation:
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