Question

One number exceeds another by 10. the sum of the numbers is 34. what are the numbers

Answer 1

To find the two numbers where one exceeds the other by 10 and they sum up to 34, we start with a variable x for the smaller number and solve for x, getting 12, and then add 10 to find the larger number, which is 22.

Step-by-step explanation:

When one number exceeds another by 10, and their sum is 34, we are dealing with a basic algebra problem. Let's assume the smaller number is x. The larger number will then be x + 10, since it exceeds the smaller by 10.

The sum of these numbers is given as 34, so we can write the equation x + (x + 10) = 34. Solving this equation involves combining like terms and isolating x:

2x + 10 = 34

2x = 34 - 10

2x = 24

x = 24/2

x = 12

Now that we have found the smaller number, x, to be 12, we can find the larger number by adding 10:

x + 10 = 12 + 10

x + 10 = 22

Therefore, the two numbers are 12 and 22.

Answer 2

Answer: 22 and 12

Step-by-step explanation:

x = y + 10
y + x = 34

Replace the x with y + 10

y + y + 10 = 34
2y + 10 = 34
2y = 24
y = 12

Now you know y, find x

x = 12 + 10
x = 22

So the numbers are 22 and 12.