Answer: Let's denote the two bases of the trapezoid as b1 and b2. Since the area of a trapezoid is given by the formula:
Step-by-step explanation: Area = (b1 + b2) * h / 2,
where h is the height of the trapezoid, we can plug in the given values to obtain:
20 = (b1 + b2) * 10 / 2
Simplifying the equation, we get:
b1 + b2 = 4
Now, we need to find two possible values of b1 and b2 that satisfy this equation. We can use the fact that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. In other words, b1 + b2 > h, or b1 + b2 > 10.
One possible solution is to set b1 = 2 and b2 = 2, since 2 + 2 = 4 and 2 + 2 > 10. In this case, the trapezoid would look like a rectangle with height 10 and bases of length 2 and 2.
Another possible solution is to set b1 = 1 and b2 = 3, since 1 + 3 = 4 and 1 + 3 > 10. In this case, the trapezoid would have a shorter base of length 1 and a longer base of length 3.
To draw a picture of the trapezoid, you can start by drawing a horizontal line to represent the height of the trapezoid, and label it with "h = 10". Then, draw two lines above the horizontal line to represent the two bases of the trapezoid, and label them with "b1" and "b2". Finally, draw two diagonal lines connecting the ends of the bases to complete the trapezoid. Make sure that the shorter base is labeled with the smaller value, and the longer base is labeled with the larger value.