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How many moles of solute are present in 5.0 L of a 5.0 M potassium nitrate (KNO3) solution?

User Kalos
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2 Answers

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How many moles of solute are present in 5.0 L of a 5.0 M potassium nitrate (KNO3) solution?

Answer:

25 moles

User Nick Vasic
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4 votes

Answer:

To determine the number of moles of solute present in a solution, we can use the formula:

moles of solute = molarity x volume (in liters)

Given that the volume of the solution is 5.0 L and the molarity is 5.0 M, we can calculate the number of moles of solute as:

moles of solute = 5.0 M x 5.0 L

moles of solute = 25 mol

Therefore, there are 25 moles of potassium nitrate (KNO3) present in 5.0 L of a 5.0 M solution.

User Sankettt
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