Question

What is the volume of solute A and the volume of solvent B you need to mix in order to create a 1 L solution which is 0.5 M? Density of A=0.4 B/mL Density of B=1.0 g/mL Molar mass of A=32 B/mol Molar mass of B=18 g/mol Volume A=400 mL Volume B=960.0 mL. Volume A=9.1 mL Volume B=990.9 mL Volume A=10.0 mL. Volume B=990.0 mL. Volume A=3.4 mL Volume B=996.6 mL Volume A=6.4 mL, Volume B=993.6 mL Volume A=200 mL Volume B=980.0 mL

Answer 1

Therefore, to create a 1 L solution of 0.5 M, you need to mix 40 mL of solute A with 960 mL of solvent B.

Step-by-step explanation:

moles of solute A = molarity × volume of solution

= 0.5 mol/L × 1 L

= 0.5 mol

mass of solute A = moles of solute A × molar mass of A

= 0.5 mol × 32 g/mol

= 16 g

volume of solute A = mass of solute A ÷ density of A

= 16 g ÷ 0.4 g/mL

= 40 mL

volume of solvent B = total volume of solution - volume of solute A

= 1000 mL - 40 mL

= 960 mL

To calculate the volume of solute A and solvent B needed to create a 0.5 M solution of 1 L, we need to use the formula:

moles of solute = molarity × volume of solution

We can start by calculating the number of moles of solute A needed:

moles of solute A = molarity × volume of solution

= 0.5 mol/L × 1 L

= 0.5 mol

Next, we can calculate the mass of solute A needed using its molar mass:

mass of solute A = moles of solute A × molar mass of A

= 0.5 mol × 32 g/mol

= 16 g

We can now use the density of solute A to calculate its volume:

volume of solute A = mass of solute A ÷ density of A

= 16 g ÷ 0.4 g/mL

= 40 mL

Finally, we can calculate the volume of solvent B needed:

volume of solvent B = total volume of solution - volume of solute A

= 1000 mL - 40 mL

= 960 mL

Therefore, to create a 1 L solution of 0.5 M, you need to mix 40 mL of solute A with 960 mL of solvent B.

We need to mix solute A and solvent B to create a 1 L solution with 0.5 M concentration.

Solute A has a density of 0.4 B/mL and a molar mass of 32 B/mol, while solvent B has a density of 1.0 g/mL and a molar mass of 18 g/mol.

To make the solution, we need to calculate the moles of solute A needed, which is 0.5 mol.

Then, we need to calculate the mass of solute A needed, which is 16 g.

Next, we use the density of A to calculate the volume of solute A needed, which is 40 mL.

Finally, we calculate the volume of solvent B needed, which is 960 mL.

In simple terms, we need 40 mL of A and 960 mL of B to make a solution that is 0.5 M in concentration.

An analogy would be mixing chocolate powder (solute A) with milk (solvent B) to make a chocolate milk drink with a specific sweetness level (0.5 M).

To summarize, we need to mix 40 mL of solute A and 960 mL of solvent B to make a 1 L solution with 0.5 M concentration, like mixing chocolate powder and milk to make a sweet chocolate milk drink.

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