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3. Pure sucrose has a melting point of 458 K. If a sample of sucrose is subjected to a temperature of 500. °F, will

sucrose be in the solid state or the liquid state?

1 Answer

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Answer:

liquid

Step-by-step explanation:

T(°F) = T(K) × 1.8 - 459.67

458×1.8=824.4

824.4-459.67=364.73

458 K = 364.73 degrees fahrenheit

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