Question

2r + 3s = 19; 6r - 3s = - 3

Answer 1

Answer: r = 2, s = 5

Explanation:

The equation is:

`\left \{ {{2r + 3s = 19} \atop {6r - 3s = -3}} \right.`

We can add both of these equations to eliminate the variable "s", making our equation:

8r = 16

r = 2

Then, we add r to any of the equations, lets say the first one, to get:

4 + 3s = 19

3s = 15

s = 5

Answer 2

s = 5

r = 2

Explanation:

2r + 3s = 19

6r - 3s = - 3

Time the first equation by -3

-6r - 9s = -57

6r - 3s = -3

-12s = -60

s = 5

Now put 5 in for s and solve for r

-6r - 9(5) = -57

-6r - 45 = -57

-6r = -12

r = 2

Let's Check

2(2) + 3(5) = 19

4 + 15 = 19

19 = 19

So, s = 5 and r = 2 is the correct answer.