Question

Please help me with my math!!

Answer 1

The given equation is in vertex form y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola. Comparing the given equation with the vertex form, we have a = -3, h = -3 and k = 4.

Since a = -3 < 0, the parabola opens downwards and has a maximum point.

To find the maximum value of y, we need to evaluate y at the x-coordinate of the vertex:

x = -3

y = -3(-3+3)^2 + 4 = 4

Therefore, the parabola y = -3(x+3)2 + 4 contains a maximum point and the maximum value of y is 4.

Hence, the answer is option C

Answer 2

C) Maximum point; 4

Explanation:

Given parabola:

`y=-3(x+3)^2+4`

The given parabola is in vertex form:

`\boxed{y = a(x - h)^2 + k}`

where:

• (h, k) is the vertex of the parabola.

• a is the leading coefficient.
  If a > 0, the parabola opens upwards.
  If a < 0, the parabola opens downwards.

By comparing the given equation with the vertex form, we can see that:

• a = -3
• h = -3
• k = 4

As a < 0, the parabola opens downwards. Therefore, the vertex of the parabola is a maximum point.

The vertex of the parabola is (h, k) = (-3, 4).

Therefore, the maximum value of y is 4, which occurs at x = -3.