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10 votes
2. What are the zeroes of P(x) = x3 – 6x2 – x +62

-6, -1, 1
A.
C. 6, -1, 1
B. -6, -1, -1
D. 6, 1, 1​

User Sally CJ
by
5.4k points

1 Answer

12 votes

Explanation:

if u mean (x^3 -6x^2 -x- 6) then the answer is C

(6,-1,1)

..................,..........

but if u mean P(x) = x3 – 6x2 – x +62

then the answer is None of the above

-2.724

4.361+1.9328i

4.361+1.9328i

User Grant Li
by
5.6k points