Answer:
16, 22, and 32.
Explanation:
Set up a system of equations to represent the situation with 3 unknown.
x + y + z = 70
z = 2x
x = y - 6 → y = x + 6
The second two equations are the y and z in terms of x, so substitute both into the first equation.
x + (x + 6) + 2x = 70
4x + 6 = 70
4x = 64
x = 16
Use this number to calculate the value of the other unknowns.
y = x + 6
y = 16 + 6
y = 22
Calculate z.
z = 2x
z = 2(16)
z = 32
So, the three numbers are 16, 22, and 32.