Question

The sum of two expressions is x2-y2-2xy+y-7. if one of them is 2x2+3y2-7y+1, find the other.

I need proper step by step answer or else I will be terminating your answer.

Answer 1

Answer:

the other expression is -x^2 - 2y^2 - 2xy + 8y - 8.

Step by step explanation:

We are given that the sum of two expressions is x^2 - y^2 - 2xy + y - 7, and we are told that one of them is 2x^2 + 3y^2 - 7y + 1. Let's call the other expression A, so we have:

A + 2x^2 + 3y^2 - 7y + 1 = x^2 - y^2 - 2xy + y - 7

Now we can rearrange this equation to solve for A:

A = x^2 - y^2 - 2xy + y - 7 - 2x^2 - 3y^2 + 7y - 1

Simplifying the right-hand side, we get:

A = -x^2 - 2y^2 - 2xy + 8y - 8

Therefore, the other expression is -x^2 - 2y^2 - 2xy + 8y - 8.

Answer 2

-x^2 - 2xy - 2y^2 + 8y - 8.

Explanation:

Let the other expression be A. Then, we have:

x^2 - y^2 - 2xy + y - 7 = (2x^2 + 3y^2 - 7y + 1) + A

Simplifying the left side:

x^2 - y^2 - 2xy + y - 7 = 2x^2 + 3y^2 - 7y + 1 + A

Rearranging the terms:

A = x^2 - y^2 - 2xy + y - 7 - 2x^2 - 3y^2 + 7y - 1

Simplifying further:

A = -x^2 - 2xy - 2y^2 + 8y - 8

Therefore, the other expression is -x^2 - 2xy - 2y^2 + 8y - 8.