Answer:
To solve the quadratic equation 9×^2-15×-6=0, we can use the quadratic formula, which is given by:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.
In this case, a = 9, b = -15, and c = -6, so we can substitute these values into the quadratic formula:
x = (-(-15) ± sqrt((-15)^2 - 4(9)(-6))) / 2(9)
Simplifying this expression gives:
x = (15 ± sqrt(225 + 216)) / 18
x = (15 ± sqrt(441)) / 18
x = (15 ± 21) / 18
So the two solutions to the quadratic equation are:
x = (15 + 21) / 18 = 2
x = (15 - 21) / 18 = -1/3
Therefore, the solutions to the quadratic equation 9×^2-15×-6=0 are x = 2 and x = -1/3.