Answer:
We can use the formula |a × b| = |a| |b| sin θ to solve for the magnitude of the cross product |a × b|, where θ is the angle between vectors a and b. In this case, we have |a × b| = 1 and θ = π/4, so we can write:
1 = |a| |b| sin(π/4)
Simplifying, we have:
|a| |b| = √2
Now, we need to find the dot product a · b. We know that:
a · b = |a| |b| cos θ
where θ is the angle between vectors a and b. Since we're given the angle between a and b, we can substitute θ = π/4 and use the value we found for |a| |b|:
a · b = (√2) cos(π/4) = (√2)/2
Therefore, a · b is equal to (√2)/2.
Explanation: