Question

Solve the system by substitution. � = y= 4 � 4x � = y= − 6 � − 30 −6x−30

Answer 1

First, isolate the y term on one side of the equation.

-For the first equation: 4x + y = 4

Subtract 4x from both sides of the equation to isolate the y term:

4x + y - 4x = 4 - 4x

y = 4 - 4x

-For the second equation: -6x - 30 + y = -6

Add 6x to both sides of the equation to isolate the y term:

-6x - 30 + y + 6x = -6 + 6x

y = -6 + 6x

Now, set the equations equal to each other to solve for x:

4 - 4x = -6 + 6x

Combine like terms to isolate the x term:

-10x = -10

Divide both sides by -10 to solve for x:

x = 1

Now plug x back into either equation to solve for y:

4 - 4(1) = 4 - 4

y = 0