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How many all.number of possible.diagonal that drawing in differnt verticle of nonagon​

User Youwhut
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It sounds like you want to find how many diagonals a nonagon has.

A nonagon has n = 9 sides.

The number of diagonals would be...


d = \text{number of diagonals}\\\\d = (n(n-3))/(2)\\\\d = (9(9-3))/(2)\\\\d = (9(6))/(2)\\\\d = (54)/(2)\\\\d = 27\\\\

A nonagon has 27 different diagonals.

Answer: 27

User Chiseled
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