Answer: 6(x+2)(x-5)
Explanation:
1: Factor by grouping- A 6 can be distributed in all 3 terms, when we do this we get 6(x²-3x-10).
2: This is in the form 6(x²+bx+c). So, to continue factoring, just forget about the six for a while and find two factors of c that add up to b. These two factors are -5 and 2.
3: Fill in the blanks with either factor. (x+?)(x+?) We get (x+2)(x-5).
4: Bring back the 6 to the beginning of the equation to get a final answer of 6(x+2)(x-5).