Question

Please help it’s very importttttt

Answer 1

Check the picture below.

`\textit{Law of Sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin( B )}{22}=\cfrac{\sin( 75^o )}{33}\implies 33\sin(B)=22\sin(75^o) \implies \sin(B)=\cfrac{22\sin(75^o)}{33} \\\\\\ B=\sin^(-1)\left( ~~ \cfrac{22\sin( 75^o)}{33} ~~\right)\implies B\approx 40.1^o`

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