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Find the equation of a line that passes through (2,10) and is parallel to the graph of y=3x+6

User Kozet
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1 Answer

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Final answer:

To find the equation of a line parallel to y = 3x + 6 and passing through (2,10), we use the point-slope form of a linear equation. Substituting the values into the formula, we find that the equation of the parallel line is y = 3x + 4.

Step-by-step explanation:

To find the equation of a line that is parallel to the graph of y = 3x + 6 and passes through the point (2, 10), we can use the fact that parallel lines have the same slope.

The given equation has a slope of 3, so the parallel line will also have a slope of 3.

Using the point-slope form of a linear equation, we can substitute the slope and the coordinates of the given point into the formula to find the equation of the parallel line:

y - y1 = m(x - x1)

Substituting the values into the formula:

y - 10 = 3(x - 2)

Simplifying the equation:

y - 10 = 3x - 6

y = 3x + 4

Therefore, the equation of the line that passes through (2,10) and is parallel to the graph of y = 3x + 6 is y = 3x + 4.

User Ncesar
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