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A car drives from a position x=6.0m to a position of x=18.0m in 6s what is its average velocity

User Dboswell
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Final answer:

The average velocity of a car that moves from x=6.0m to x=18.0m in 6s is 2.0 m/s.

Step-by-step explanation:

To calculate the average velocity of a car, we need to know the total displacement and the total time taken for the displacement.

Displacement is the difference between the final position and the initial position, and average velocity is displacement divided by time.

The car moves from an initial position of xi=6.0 m to a final position of xf=18.0 m.

Therefore, the displacement (Δx) is xf - xi = 18.0 m - 6.0 m = 12.0 m.

The time taken (Δt) is 6 seconds.

Thus, the average velocity (Š) of the car is:

Š = Δx / Δt

= 12.0 m / 6 s

= 2.0 m/s

This average velocity is a vector quantity and should be given a direction to fully describe the motion of the car.

User Brittanie
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