Question

What is the formula for Gold (III) bromide?

Answer 1

The formula for Gold (III) bromide is AuBr3, consisting of one gold ion and three bromide ions to balance the overall charge.

Step-by-step explanation:

The formula for Gold(III) bromide is AuBr₃, reflecting gold in the +3 oxidation state denoted by the III in Gold(III). Each bromide ion (Br-) carries a -1 charge. To balance the overall charge to +3 for gold, three bromide ions are required. Consequently, the chemical formula AuBr₃ represents the combination of one gold ion (Au³⁺) with three bromide ions (Br⁻), ensuring electrical neutrality. Gold(III) bromide exemplifies the precise stoichiometry and charge balancing essential in chemical compounds, adhering to the principles of ionic bonding and oxidation states that govern the formation of stable and electrically neutral compounds.

Answer 2

The formula for Gold (III) bromide is AuBr3. This compound is composed of one gold atom (Au) and three bromine atoms (Br).

Step-by-step explanation:

The formula for Gold (III) bromide is AuBr3. This compound is composed of one gold atom (Au) and three bromine atoms (Br). To determine the formula, we need to consider the charges of the elements involved. Gold (Au) has a charge of +3 in this compound, indicated by the Roman numeral III in parentheses. Bromine (Br) has a charge of -1. Since the charges must balance in a compound, we can determine the formula by "swapping" the charges. The +3 charge of gold will cancel out the -1 charge of bromine. To balance the charges, we need three bromine atoms, each contributing a -1 charge, for a total of -3. Therefore, the formula for Gold (III) bromide is AuBr3, with one gold atom and three bromine atoms.