Question

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Answer 1

3 mol AlCl₃.

Step-by-step explanation:

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In this case, according to the specified reactants and products, it is possible to set up the following balanced chemical reaction:

`Al(NO_3)_3+3NaCl\rightarrow 3NaNO_3+AlCl_3`

Whereas we evidence the 1:3 mole ratio between aluminum nitrate and sodium chloride; thus, since different moles were reacting, we need to identify the limiting reactant by computing the moles of AlCl₃ produced by each reactant as follows:

`n_(AlCl_3)^(by\ Al(NO_3)_3)=4molAl(NO_3)_3*(1molAlCl_3)/(1molAl(NO_3)_3) =4molAlCl_3\\\\n_(AlCl_3)^(by\ NaCl)=9molNaCl*(1molAlCl_3)/(3molNaCl) =3molAlCl_3`

Thus, we infer that NaCl is the limiting reactant as it produces the fewest moles of AlCl₃; consequently the produced amount of this product is 3 mol.

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